(Q1) Two men on either side of a temple of 30 meter height observe its top at the angles of elevation 30^o and 60^o respectively. Find the distance between the two men.

Solution :

Height of the temple BD = 30 meter

Angle of elevation of one person ∠BAD = 30^o

Angle of elevation of another person ∠BCD = 60^o

Let the distance between the first person and the temple, AD = x and distance between the second person and the temple, CD = d

From ∆BAD

x = √ .....(1)

From ∆BCD

from (1) and (2) distance between the persons = BC + BA = x + d